Salesforce Record Balancing - Salesforce Online Assessment

Problem Preview

"You're a Salesforce admin getting ready to spin up several scratch orgs for a big demo. Each scratch org needs to ship with exactly the same seed data — the same number of records in every custom field — so your demo looks flawless across environments. The counts you already have live in the array `recordCounts`, where `recordCounts[i]` is the number of seed records you've pre-loaded for the i-th custom field. To build the orgs, the record count in every field must be perfectly divisible by the number of orgs you create (k, where k >= 2). You can insert new seed records or delete extras; each insert or delete is one modification. Your goal is to find the fewest total modifications required to spin up at least 2 identical scratch orgs. Example n = 5 recordCounts = [4, 7, 5, 11, 15] For 2 orgs the per-field changes are [0, 1, 1, 1, 1] -> total 4. For 3 orgs they are [1, 1, 1, 1, 0] -> total 4. Any org count k >= 2 is allowed, but the minimum achievable number of modifications is 4. Function Description Complete the function getMinimumRecords in the editor below. getMinimumRecords has the following parameter: * int recordCounts[n]: the current number of records for each field Returns * int: the minimal number of modifications (adds or deletes) needed to form at least 2 equal templates Constraints * 1 <= n <= 10^5 * 1 <= recordCounts[i] <= 10^9 Sample Case 0 Sample Input 5 3 8 7 6 4 Sample Output 2 Explanation With 2 orgs the adjustments are [+1, 0, -1, 0, 0] -> 2 total modifications, which is optimal."